java ints over 9 digits?

[dasoldier]

how can I make an int that can be up to 20 digits?

I pull errors over 9 digits?

 

[pxc]

Doesn't Java support native decimal types now? PCs support 80 bit integers, which are 24 digits long (signed) or 25 digits long (unsigned).

 

[BillLeeLee]

The long primitive type supports 19 digit integers in the range of -2^63 to (2^63)-1

 

[Zalbag]

Looking at the Java API, there's 2 classes in java.math: BigDecimal and BigInteger.

 

[nameless_centurian]

Doesn't Java support native decimal types now? PCs support 80 bit integers, which are 24 digits long (signed) or 25 digits long (unsigned).

not sure where you're getting this 80-bit thing.

if the word size is 32, a double word would be 64...

so you're telling me there is a datatype that will handle double word + short int size?

do i understand correctly?

 

[pxc]

not sure where you're getting this 80-bit thing.

Ignore that above. I was mixing up FPU BCD (80 bit) and native long integer FPU support (64-bit).

The FPU performs floating point math internally at extended precision (80-bit) whether you're using standard precision (64-bit) or extended precision. The 80-bit register can be used for 80-bit BCD (IIRC only 17 digits are usable).

I haven't done any x87 assembly in a while so it's a little fuzzy to me now and i'm starting to take .NET's decimal type (128-bit, to 28 sig. digits) for granted.